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(6x-1)(5x+2)=0
We multiply parentheses ..
(+30x^2+12x-5x-2)=0
We get rid of parentheses
30x^2+12x-5x-2=0
We add all the numbers together, and all the variables
30x^2+7x-2=0
a = 30; b = 7; c = -2;
Δ = b2-4ac
Δ = 72-4·30·(-2)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-17}{2*30}=\frac{-24}{60} =-2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+17}{2*30}=\frac{10}{60} =1/6 $
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