(6x-1)(4x+9)=(3x+5)(8x-2)

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Solution for (6x-1)(4x+9)=(3x+5)(8x-2) equation: 



(6x-1)(4x+9)=(3x+5)(8x-2)

We move all terms to the left:

(6x-1)(4x+9)-((3x+5)(8x-2))=0

We multiply parentheses ..

(+24x^2+54x-4x-9)-((3x+5)(8x-2))=0



We calculate terms in parentheses: -((3x+5)(8x-2)), so:

(3x+5)(8x-2)

We multiply parentheses ..

(+24x^2-6x+40x-10)

We get rid of parentheses

24x^2-6x+40x-10

We add all the numbers together, and all the variables

24x^2+34x-10

Back to the equation:

-(24x^2+34x-10)



We get rid of parentheses

24x^2-24x^2+54x-4x-34x-9+10=0

We add all the numbers together, and all the variables

16x+1=0

We move all terms containing x to the left, all other terms to the right

16x=-1

x=-1/16

x=-1/16

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