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(6x+7/7)-3=(5x-3/8)
We move all terms to the left:
(6x+7/7)-3-((5x-3/8))=0
We add all the numbers together, and all the variables
(6x+1)-((+5x-3/8))-3=0
We get rid of parentheses
6x-((+5x-3/8))+1-3=0
We multiply all the terms by the denominator
6x*8))-((+5x-3+1*8))-3*8))=0
We add all the numbers together, and all the variables
6x*8))-((5x+5))-3*8))=0
We add all the numbers together, and all the variables
6x*8))-((5x=0
Wy multiply elements
48x^2=0
a = 48; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·48·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{96}=0$
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