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(6x+7)-(2x-9)x=4
We move all terms to the left:
(6x+7)-(2x-9)x-(4)=0
We multiply parentheses
-2x^2+(6x+7)+9x-4=0
We get rid of parentheses
-2x^2+6x+9x+7-4=0
We add all the numbers together, and all the variables
-2x^2+15x+3=0
a = -2; b = 15; c = +3;
Δ = b2-4ac
Δ = 152-4·(-2)·3
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{249}}{2*-2}=\frac{-15-\sqrt{249}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{249}}{2*-2}=\frac{-15+\sqrt{249}}{-4} $
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