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(6x+6)=1+(x-8)
We move all terms to the left:
(6x+6)-(1+(x-8))=0
We get rid of parentheses
6x-(1+(x-8))+6=0
We calculate terms in parentheses: -(1+(x-8)), so:We get rid of parentheses
1+(x-8)
determiningTheFunctionDomain (x-8)+1
We get rid of parentheses
x-8+1
We add all the numbers together, and all the variables
x-7
Back to the equation:
-(x-7)
6x-x+7+6=0
We add all the numbers together, and all the variables
5x+13=0
We move all terms containing x to the left, all other terms to the right
5x=-13
x=-13/5
x=-2+3/5
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