(6x+4)(6x-10)=0

Solution for (6x+4)(6x-10)=0 equation:

(6x+4)(6x-10)=0

We multiply parentheses ..

(+36x^2-60x+24x-40)=0

We get rid of parentheses

36x^2-60x+24x-40=0

We add all the numbers together, and all the variables

36x^2-36x-40=0

a = 36; b = -36; c = -40;
Δ = b2-4ac
Δ = -362-4·36·(-40)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-84}{2*36}=\frac{-48}{72}
=-2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+84}{2*36}=\frac{120}{72}
=1+2/3
$