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(6x+4)(5x-4)=0
We multiply parentheses ..
(+30x^2-24x+20x-16)=0
We get rid of parentheses
30x^2-24x+20x-16=0
We add all the numbers together, and all the variables
30x^2-4x-16=0
a = 30; b = -4; c = -16;
Δ = b2-4ac
Δ = -42-4·30·(-16)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-44}{2*30}=\frac{-40}{60} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+44}{2*30}=\frac{48}{60} =4/5 $
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