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(6x+4)(4x+26)=110
We move all terms to the left:
(6x+4)(4x+26)-(110)=0
We multiply parentheses ..
(+24x^2+156x+16x+104)-110=0
We get rid of parentheses
24x^2+156x+16x+104-110=0
We add all the numbers together, and all the variables
24x^2+172x-6=0
a = 24; b = 172; c = -6;
Δ = b2-4ac
Δ = 1722-4·24·(-6)
Δ = 30160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{30160}=\sqrt{16*1885}=\sqrt{16}*\sqrt{1885}=4\sqrt{1885}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(172)-4\sqrt{1885}}{2*24}=\frac{-172-4\sqrt{1885}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(172)+4\sqrt{1885}}{2*24}=\frac{-172+4\sqrt{1885}}{48} $
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