(6x+31)+(6x+31)=(19x-36)

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Solution for (6x+31)+(6x+31)=(19x-36) equation: 



(6x+31)+(6x+31)=(19x-36)

We move all terms to the left:

(6x+31)+(6x+31)-((19x-36))=0

We get rid of parentheses

6x+6x-((19x-36))+31+31=0



We calculate terms in parentheses: -((19x-36)), so:

(19x-36)

We get rid of parentheses

19x-36

Back to the equation:

-(19x-36)



We add all the numbers together, and all the variables

12x-(19x-36)+62=0

We get rid of parentheses

12x-19x+36+62=0

We add all the numbers together, and all the variables

-7x+98=0

We move all terms containing x to the left, all other terms to the right

-7x=-98

x=-98/-7

x=+14

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