(6x+30)+(3x-12)=180

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Solution for (6x+30)+(3x-12)=180 equation: 



(6x+30)+(3x-12)=180

We move all terms to the left:

(6x+30)+(3x-12)-(180)=0

We get rid of parentheses

6x+3x+30-12-180=0

We add all the numbers together, and all the variables

9x-162=0

We move all terms containing x to the left, all other terms to the right

9x=162

x=162/9

x=18

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