(6x+3)/7=(2x-4)/2

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Solution for (6x+3)/7=(2x-4)/2 equation: 


x in (-oo:+oo)

(6*x+3)/7 = (2*x-4)/2 // - (2*x-4)/2

(6*x+3)/7-((2*x-4)/2) = 0

(6*x+3)/7+(-1*(2*x-4))/2 = 0

(2*(6*x+3))/(2*7)+(-1*7*(2*x-4))/(2*7) = 0

2*(6*x+3)-1*7*(2*x-4) = 0

34-2*x = 0

(34-2*x)/(2*7) = 0

(34-2*x)/(2*7) = 0 // * 2*7

34-2*x = 0

34-2*x = 0 // - 34

-2*x = -34 // : -2

x = -34/(-2)

x = 17

x = 17

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