(6x+3)/10=(x+2)/20

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Solution for (6x+3)/10=(x+2)/20 equation: 



(6x+3)/10=(x+2)/20

We move all terms to the left:

(6x+3)/10-((x+2)/20)=0

We calculate fractions


6x/()+(-((x+2)*10)/()=0



We calculate terms in parentheses: +(-((x+2)*10)/(), so:

-((x+2)*10)/(

We multiply all the terms by the denominator


-((x+2)*10)



We calculate terms in parentheses: -((x+2)*10), so:

(x+2)*10

We multiply parentheses

10x+20

Back to the equation:

-(10x+20)



We get rid of parentheses

-10x-20

Back to the equation:

+(-10x-20)



We get rid of parentheses

6x/()-10x-20=0

We multiply all the terms by the denominator


6x-10x*()-20*()=0

We add all the numbers together, and all the variables

6x-10x*()=0

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