(6x+3)+(4x-3)+(6x+3)=180

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Solution for (6x+3)+(4x-3)+(6x+3)=180 equation: 



(6x+3)+(4x-3)+(6x+3)=180

We move all terms to the left:

(6x+3)+(4x-3)+(6x+3)-(180)=0

We get rid of parentheses

6x+4x+6x+3-3+3-180=0

We add all the numbers together, and all the variables

16x-177=0

We move all terms containing x to the left, all other terms to the right

16x=177

x=177/16

x=11+1/16

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