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(6x+2)=(-10+3x)
We move all terms to the left:
(6x+2)-((-10+3x))=0
We add all the numbers together, and all the variables
(6x+2)-((3x-10))=0
We get rid of parentheses
6x-((3x-10))+2=0
We calculate terms in parentheses: -((3x-10)), so:We get rid of parentheses
(3x-10)
We get rid of parentheses
3x-10
Back to the equation:
-(3x-10)
6x-3x+10+2=0
We add all the numbers together, and all the variables
3x+12=0
We move all terms containing x to the left, all other terms to the right
3x=-12
x=-12/3
x=-4
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