(6x+19)+(2x+5)+(3x-11)=180

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Solution for (6x+19)+(2x+5)+(3x-11)=180 equation: 



(6x+19)+(2x+5)+(3x-11)=180

We move all terms to the left:

(6x+19)+(2x+5)+(3x-11)-(180)=0

We get rid of parentheses

6x+2x+3x+19+5-11-180=0

We add all the numbers together, and all the variables

11x-167=0

We move all terms containing x to the left, all other terms to the right

11x=167

x=167/11

x=15+2/11

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