(6x+18)1x=(x+93)1x

Solution for (6x+18)1x=(x+93)1x equation:

(6x+18)1x=(x+93)1x

We move all terms to the left:

(6x+18)1x-((x+93)1x)=0

We multiply parentheses

6x^2+18x-((x+93)1x)=0


We calculate terms in parentheses: -((x+93)1x), so:

(x+93)1x

We multiply parentheses

x^2+93x

Back to the equation:

-(x^2+93x)


We get rid of parentheses

6x^2-x^2+18x-93x=0

We add all the numbers together, and all the variables

5x^2-75x=0

a = 5; b = -75; c = 0;
Δ = b2-4ac
Δ = -752-4·5·0
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5625}=75$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-75}{2*5}=\frac{0}{10}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+75}{2*5}=\frac{150}{10}
=15
$