(6x+16)=(3x+14)+(2x+20)

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Solution for (6x+16)=(3x+14)+(2x+20) equation: 



(6x+16)=(3x+14)+(2x+20)

We move all terms to the left:

(6x+16)-((3x+14)+(2x+20))=0

We get rid of parentheses

6x-((3x+14)+(2x+20))+16=0



We calculate terms in parentheses: -((3x+14)+(2x+20)), so:

(3x+14)+(2x+20)

We get rid of parentheses

3x+2x+14+20

We add all the numbers together, and all the variables

5x+34

Back to the equation:

-(5x+34)



We get rid of parentheses

6x-5x-34+16=0

We add all the numbers together, and all the variables

x-18=0

We move all terms containing x to the left, all other terms to the right

x=18

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