(6x+14)+(3x+29)=100

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Solution for (6x+14)+(3x+29)=100 equation: 



(6x+14)+(3x+29)=100

We move all terms to the left:

(6x+14)+(3x+29)-(100)=0

We get rid of parentheses

6x+3x+14+29-100=0

We add all the numbers together, and all the variables

9x-57=0

We move all terms containing x to the left, all other terms to the right

9x=57

x=57/9

x=6+1/3

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