(6x+12)=(3x-12)+78

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Solution for (6x+12)=(3x-12)+78 equation: 



(6x+12)=(3x-12)+78

We move all terms to the left:

(6x+12)-((3x-12)+78)=0

We get rid of parentheses

6x-((3x-12)+78)+12=0



We calculate terms in parentheses: -((3x-12)+78), so:

(3x-12)+78

We get rid of parentheses

3x-12+78

We add all the numbers together, and all the variables

3x+66

Back to the equation:

-(3x+66)



We get rid of parentheses

6x-3x-66+12=0

We add all the numbers together, and all the variables

3x-54=0

We move all terms containing x to the left, all other terms to the right

3x=54

x=54/3

x=18

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