(6x+11)+(10x+3)=(13x-5)=180

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Solution for (6x+11)+(10x+3)=(13x-5)=180 equation:



(6x+11)+(10x+3)=(13x-5)=180
We move all terms to the left:
(6x+11)+(10x+3)-((13x-5))=0
We get rid of parentheses
6x+10x-((13x-5))+11+3=0
We calculate terms in parentheses: -((13x-5)), so:
(13x-5)
We get rid of parentheses
13x-5
Back to the equation:
-(13x-5)
We add all the numbers together, and all the variables
16x-(13x-5)+14=0
We get rid of parentheses
16x-13x+5+14=0
We add all the numbers together, and all the variables
3x+19=0
We move all terms containing x to the left, all other terms to the right
3x=-19
x=-19/3
x=-6+1/3

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