(6x+10)x=(x+2)

Solution for (6x+10)x=(x+2) equation:

(6x+10)x=(x+2)

We move all terms to the left:

(6x+10)x-((x+2))=0

We multiply parentheses

6x^2+10x-((x+2))=0


We calculate terms in parentheses: -((x+2)), so:

(x+2)

We get rid of parentheses

x+2

Back to the equation:

-(x+2)


We get rid of parentheses

6x^2+10x-x-2=0

We add all the numbers together, and all the variables

6x^2+9x-2=0

a = 6; b = 9; c = -2;
Δ = b2-4ac
Δ = 92-4·6·(-2)
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{129}}{2*6}=\frac{-9-\sqrt{129}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{129}}{2*6}=\frac{-9+\sqrt{129}}{12}
$