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(6x+1)=(8+3x)
We move all terms to the left:
(6x+1)-((8+3x))=0
We add all the numbers together, and all the variables
(6x+1)-((3x+8))=0
We get rid of parentheses
6x-((3x+8))+1=0
We calculate terms in parentheses: -((3x+8)), so:We get rid of parentheses
(3x+8)
We get rid of parentheses
3x+8
Back to the equation:
-(3x+8)
6x-3x-8+1=0
We add all the numbers together, and all the variables
3x-7=0
We move all terms containing x to the left, all other terms to the right
3x=7
x=7/3
x=2+1/3
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