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(6x+1)=(5x+19)
We move all terms to the left:
(6x+1)-((5x+19))=0
We get rid of parentheses
6x-((5x+19))+1=0
We calculate terms in parentheses: -((5x+19)), so:We get rid of parentheses
(5x+19)
We get rid of parentheses
5x+19
Back to the equation:
-(5x+19)
6x-5x-19+1=0
We add all the numbers together, and all the variables
x-18=0
We move all terms containing x to the left, all other terms to the right
x=18
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