(6x+1)+(3x-10)+(x-19)=180

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Solution for (6x+1)+(3x-10)+(x-19)=180 equation: 



(6x+1)+(3x-10)+(x-19)=180

We move all terms to the left:

(6x+1)+(3x-10)+(x-19)-(180)=0

We get rid of parentheses

6x+3x+x+1-10-19-180=0

We add all the numbers together, and all the variables

10x-208=0

We move all terms containing x to the left, all other terms to the right

10x=208

x=208/10

x=20+4/5

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