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(6x+1)(6x-1)=x
We move all terms to the left:
(6x+1)(6x-1)-(x)=0
We add all the numbers together, and all the variables
-1x+(6x+1)(6x-1)=0
We use the square of the difference formula
36x^2-1x-1=0
a = 36; b = -1; c = -1;
Δ = b2-4ac
Δ = -12-4·36·(-1)
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{145}}{2*36}=\frac{1-\sqrt{145}}{72} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{145}}{2*36}=\frac{1+\sqrt{145}}{72} $
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