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(6x+1)(5x-4)=0
We multiply parentheses ..
(+30x^2-24x+5x-4)=0
We get rid of parentheses
30x^2-24x+5x-4=0
We add all the numbers together, and all the variables
30x^2-19x-4=0
a = 30; b = -19; c = -4;
Δ = b2-4ac
Δ = -192-4·30·(-4)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-29}{2*30}=\frac{-10}{60} =-1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+29}{2*30}=\frac{48}{60} =4/5 $
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