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(6x)(x-23)=180
We move all terms to the left:
(6x)(x-23)-(180)=0
We multiply parentheses
6x^2-138x-180=0
a = 6; b = -138; c = -180;
Δ = b2-4ac
Δ = -1382-4·6·(-180)
Δ = 23364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{23364}=\sqrt{36*649}=\sqrt{36}*\sqrt{649}=6\sqrt{649}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-138)-6\sqrt{649}}{2*6}=\frac{138-6\sqrt{649}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-138)+6\sqrt{649}}{2*6}=\frac{138+6\sqrt{649}}{12} $
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