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(6x)(2x-1)=90
We move all terms to the left:
(6x)(2x-1)-(90)=0
We multiply parentheses
12x^2-6x-90=0
a = 12; b = -6; c = -90;
Δ = b2-4ac
Δ = -62-4·12·(-90)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-66}{2*12}=\frac{-60}{24} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+66}{2*12}=\frac{72}{24} =3 $
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