(6x^2-7x+5)/(2x-3)

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Solution for (6x^2-7x+5)/(2x-3) equation: 


D( x )

2*x-3 = 0

2*x-3 = 0

2*x-3 = 0

2*x-3 = 0 // + 3

2*x = 3 // : 2

x = 3/2

x in (-oo:3/2) U (3/2:+oo)

(6*x^2-(7*x)+5)/(2*x-3) = 0

(6*x^2-7*x+5)/(2*x-3) = 0

6*x^2-7*x+5 = 0

6*x^2-7*x+5 = 0

DELTA = (-7)^2-(4*5*6)

DELTA = -71

DELTA < 0

1 = 0

1/(2*x-3) = 0

x belongs to the empty set

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