(6r-5)(6r+1)=0

Solution for (6r-5)(6r+1)=0 equation:

(6r-5)(6r+1)=0

We multiply parentheses ..

(+36r^2+6r-30r-5)=0

We get rid of parentheses

36r^2+6r-30r-5=0

We add all the numbers together, and all the variables

36r^2-24r-5=0

a = 36; b = -24; c = -5;
Δ = b2-4ac
Δ = -242-4·36·(-5)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-36}{2*36}=\frac{-12}{72}
=-1/6
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+36}{2*36}=\frac{60}{72}
=5/6
$