(6r-1)6r=11

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Solution for (6r-1)6r=11 equation:



(6r-1)6r=11
We move all terms to the left:
(6r-1)6r-(11)=0
We multiply parentheses
36r^2-6r-11=0
a = 36; b = -6; c = -11;
Δ = b2-4ac
Δ = -62-4·36·(-11)
Δ = 1620
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{1620}=\sqrt{324*5}=\sqrt{324}*\sqrt{5}=18\sqrt{5}$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-18\sqrt{5}}{2*36}=\frac{6-18\sqrt{5}}{72} $
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+18\sqrt{5}}{2*36}=\frac{6+18\sqrt{5}}{72} $

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