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(6p-12)=(3p)
We move all terms to the left:
(6p-12)-((3p))=0
determiningTheFunctionDomain (6p-12)-3p=0
We add all the numbers together, and all the variables
-3p+(6p-12)=0
We get rid of parentheses
-3p+6p-12=0
We add all the numbers together, and all the variables
3p-12=0
We move all terms containing p to the left, all other terms to the right
3p=12
p=12/3
p=4
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