(6n-5q)/11=c

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Solution for (6n-5q)/11=c equation: 


x in (-oo:+oo)

(6*n-(5*q))/11 = c // - c

(6*n-(5*q))/11-c = 0

(6*n-5*q)/11-c = 0

(6*n-5*q)/11+(11*(-c))/11 = 0

11*(-c)+6*n-5*q = 0

6*n-11*c-5*q = 0

(6*n-11*c-5*q)/11 = 0

(6*n-11*c-5*q)/11 = 0 // * 11

6*n-11*c-5*q = 0

x belongs to the empty set

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