(6n+7/3n-2n)=(4n+5/2n+3)

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Solution for (6n+7/3n-2n)=(4n+5/2n+3) equation: 



(6n+7/3n-2n)=(4n+5/2n+3)

We move all terms to the left:

(6n+7/3n-2n)-((4n+5/2n+3))=0



Domain of the equation: 3n-2n)!=0

n∈R





Domain of the equation: 2n+3))!=0

n∈R



We add all the numbers together, and all the variables

(+4n+7/3n)-((4n+5/2n+3))=0

We get rid of parentheses

4n+7/3n-((4n+5/2n+3))=0

We calculate fractions


4n+14n/6n^2+(-((4n+5*3n)/6n^2=0

We add all the numbers together, and all the variables

4n+14n/6n^2+(-((+4n+5*3n)/6n^2=0

We multiply all the terms by the denominator


4n*6n^2+14n+(-((+4n+5*3n)=0



We calculate terms in parentheses: +(-((+4n+5*3n), so:

-((+4n+5*3n



We add all the numbers together, and all the variables

14n+4n*6n^2+(-((+4n+5*3n)=0

Wy multiply elements

24n^3+14n+(-((+4n+5*3n)=0



We calculate terms in parentheses: +(-((+4n+5*3n), so:

-((+4n+5*3n



We do not support enpression: n^3

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