(6m-3)7=(2m+1)/7

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Solution for (6m-3)7=(2m+1)/7 equation: 



(6m-3)7=(2m+1)/7

We move all terms to the left:

(6m-3)7-((2m+1)/7)=0

We multiply parentheses

42m-((2m+1)/7)-21=0

We multiply all the terms by the denominator


42m*7)-((2m+1)-21*7)=0

We add all the numbers together, and all the variables

42m*7)-((2m+1)=0

Wy multiply elements

294m^2=0

a = 294; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·294·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{588}=0$

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