(6m+1)(m+7)=0

Solution for (6m+1)(m+7)=0 equation:

(6m+1)(m+7)=0

We multiply parentheses ..

(+6m^2+42m+m+7)=0

We get rid of parentheses

6m^2+42m+m+7=0

We add all the numbers together, and all the variables

6m^2+43m+7=0

a = 6; b = 43; c = +7;
Δ = b2-4ac
Δ = 432-4·6·7
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1681}=41$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-41}{2*6}=\frac{-84}{12}
=-7
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+41}{2*6}=\frac{-2}{12}
=-1/6
$