(6k+12)(k-8)=0

Solution for (6k+12)(k-8)=0 equation:

(6k+12)(k-8)=0

We multiply parentheses ..

(+6k^2-48k+12k-96)=0

We get rid of parentheses

6k^2-48k+12k-96=0

We add all the numbers together, and all the variables

6k^2-36k-96=0

a = 6; b = -36; c = -96;
Δ = b2-4ac
Δ = -362-4·6·(-96)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-60}{2*6}=\frac{-24}{12}
=-2
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+60}{2*6}=\frac{96}{12}
=8
$