(6h+5)(h+3)=0

Solution for (6h+5)(h+3)=0 equation:

(6h+5)(h+3)=0

We multiply parentheses ..

(+6h^2+18h+5h+15)=0

We get rid of parentheses

6h^2+18h+5h+15=0

We add all the numbers together, and all the variables

6h^2+23h+15=0

a = 6; b = 23; c = +15;
Δ = b2-4ac
Δ = 232-4·6·15
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-13}{2*6}=\frac{-36}{12}
=-3
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+13}{2*6}=\frac{-10}{12}
=-5/6
$