(6f-7)(8f=9)

Solution for (6f-7)(8f=9) equation:

(6f-7)(8f=9)

We move all terms to the left:

(6f-7)(8f-(9))=0

We multiply parentheses ..

(+48f^2-54f-56f+63)=0

We get rid of parentheses

48f^2-54f-56f+63=0

We add all the numbers together, and all the variables

48f^2-110f+63=0

a = 48; b = -110; c = +63;
Δ = b2-4ac
Δ = -1102-4·48·63
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-110)-2}{2*48}=\frac{108}{96}
=1+1/8
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-110)+2}{2*48}=\frac{112}{96}
=1+1/6
$