(6d-4)(4d+9)=0

Solution for (6d-4)(4d+9)=0 equation:

(6d-4)(4d+9)=0

We multiply parentheses ..

(+24d^2+54d-16d-36)=0

We get rid of parentheses

24d^2+54d-16d-36=0

We add all the numbers together, and all the variables

24d^2+38d-36=0

a = 24; b = 38; c = -36;
Δ = b2-4ac
Δ = 382-4·24·(-36)
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(38)-70}{2*24}=\frac{-108}{48}
=-2+1/4
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(38)+70}{2*24}=\frac{32}{48}
=2/3
$