(6b+1)=4(b-5)-2

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Solution for (6b+1)=4(b-5)-2 equation:


Simplifying
(6b + 1) = 4(b + -5) + -2

Reorder the terms:
(1 + 6b) = 4(b + -5) + -2

Remove parenthesis around (1 + 6b)
1 + 6b = 4(b + -5) + -2

Reorder the terms:
1 + 6b = 4(-5 + b) + -2
1 + 6b = (-5 * 4 + b * 4) + -2
1 + 6b = (-20 + 4b) + -2

Reorder the terms:
1 + 6b = -20 + -2 + 4b

Combine like terms: -20 + -2 = -22
1 + 6b = -22 + 4b

Solving
1 + 6b = -22 + 4b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4b' to each side of the equation.
1 + 6b + -4b = -22 + 4b + -4b

Combine like terms: 6b + -4b = 2b
1 + 2b = -22 + 4b + -4b

Combine like terms: 4b + -4b = 0
1 + 2b = -22 + 0
1 + 2b = -22

Add '-1' to each side of the equation.
1 + -1 + 2b = -22 + -1

Combine like terms: 1 + -1 = 0
0 + 2b = -22 + -1
2b = -22 + -1

Combine like terms: -22 + -1 = -23
2b = -23

Divide each side by '2'.
b = -11.5

Simplifying
b = -11.5

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