(6b+1)(3b+8)=0

Solution for (6b+1)(3b+8)=0 equation:

(6b+1)(3b+8)=0

We multiply parentheses ..

(+18b^2+48b+3b+8)=0

We get rid of parentheses

18b^2+48b+3b+8=0

We add all the numbers together, and all the variables

18b^2+51b+8=0

a = 18; b = 51; c = +8;
Δ = b2-4ac
Δ = 512-4·18·8
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(51)-45}{2*18}=\frac{-96}{36}
=-2+2/3
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(51)+45}{2*18}=\frac{-6}{36}
=-1/6
$