(6a-4)=(4a+28)

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Solution for (6a-4)=(4a+28) equation:



(6a-4)=(4a+28)
We move all terms to the left:
(6a-4)-((4a+28))=0
We get rid of parentheses
6a-((4a+28))-4=0
We calculate terms in parentheses: -((4a+28)), so:
(4a+28)
We get rid of parentheses
4a+28
Back to the equation:
-(4a+28)
We get rid of parentheses
6a-4a-28-4=0
We add all the numbers together, and all the variables
2a-32=0
We move all terms containing a to the left, all other terms to the right
2a=32
a=32/2
a=16

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