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(6a+6)(7a+5)=0
We multiply parentheses ..
(+42a^2+30a+42a+30)=0
We get rid of parentheses
42a^2+30a+42a+30=0
We add all the numbers together, and all the variables
42a^2+72a+30=0
a = 42; b = 72; c = +30;
Δ = b2-4ac
Δ = 722-4·42·30
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-12}{2*42}=\frac{-84}{84} =-1 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+12}{2*42}=\frac{-60}{84} =-5/7 $
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