(6a+42)=(28a-12)

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Solution for (6a+42)=(28a-12) equation: 



(6a+42)=(28a-12)

We move all terms to the left:

(6a+42)-((28a-12))=0

We get rid of parentheses

6a-((28a-12))+42=0



We calculate terms in parentheses: -((28a-12)), so:

(28a-12)

We get rid of parentheses

28a-12

Back to the equation:

-(28a-12)



We get rid of parentheses

6a-28a+12+42=0

We add all the numbers together, and all the variables

-22a+54=0

We move all terms containing a to the left, all other terms to the right

-22a=-54

a=-54/-22

a=2+5/11

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