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(600/x+5)(x-4)=600
We move all terms to the left:
(600/x+5)(x-4)-(600)=0
Domain of the equation: x+5)(x-4)!=0We multiply parentheses ..
x∈R
(+600x^2-2400x+5x-20)-600=0
We get rid of parentheses
600x^2-2400x+5x-20-600=0
We add all the numbers together, and all the variables
600x^2-2395x-620=0
a = 600; b = -2395; c = -620;
Δ = b2-4ac
Δ = -23952-4·600·(-620)
Δ = 7224025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7224025}=\sqrt{25*288961}=\sqrt{25}*\sqrt{288961}=5\sqrt{288961}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2395)-5\sqrt{288961}}{2*600}=\frac{2395-5\sqrt{288961}}{1200} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2395)+5\sqrt{288961}}{2*600}=\frac{2395+5\sqrt{288961}}{1200} $
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