(6/a)-12=(12/3a)

Solution for (6/a)-12=(12/3a) equation:

D( a )

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

6/a-12 = (12/3)*a // - (12/3)*a

6/a-((12/3)*a)-12 = 0

6/a-4*a-12 = 0

6*a^-1-4*a^1-12*a^0 = 0

(6*a^0-4*a^2-12*a^1)/(a^1) = 0 // * a^2

a^1*(6*a^0-4*a^2-12*a^1) = 0

a^1

6-4*a^2-12*a = 0

6-4*a^2-12*a = 0

DELTA = (-12)^2-(-4*4*6)

DELTA = 240

DELTA > 0

a = (240^(1/2)+12)/(-4*2) or a = (12-240^(1/2))/(-4*2)

a = (4*15^(1/2)+12)/(-8) or a = (12-4*15^(1/2))/(-8)

a in { (4*15^(1/2)+12)/(-8), (12-4*15^(1/2))/(-8)} 

a in { (4*15^(1/2)+12)/(-8), (12-4*15^(1/2))/(-8) }