(6/7)y=5

Solution for (6/7)y=5 equation:

(6/7)y=5

We move all terms to the left:

(6/7)y-(5)=0


Domain of the equation: 7)y!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+6/7)y-5=0

We multiply parentheses

6y^2-5=0

a = 6; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·6·(-5)
Δ = 120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{120}=\sqrt{4*30}=\sqrt{4}*\sqrt{30}=2\sqrt{30}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{30}}{2*6}=\frac{0-2\sqrt{30}}{12}
=-\frac{2\sqrt{30}}{12}
=-\frac{\sqrt{30}}{6}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{30}}{2*6}=\frac{0+2\sqrt{30}}{12}
=\frac{2\sqrt{30}}{12}
=\frac{\sqrt{30}}{6}
$