(6/2)2-15x2/1=5

Solution for (6/2)2-15x2/1=5 equation:

(6/2)2-15x^2/1=5

We move all terms to the left:

(6/2)2-15x^2/1-(5)=0

determiningTheFunctionDomain
-15x^2/1-5+(6/2)2=0

We add all the numbers together, and all the variables

-15x^2/1-5+32=0

We add all the numbers together, and all the variables

-15x^2/1+27=0

We multiply all the terms by the denominator


-15x^2+27*1=0

We add all the numbers together, and all the variables

-15x^2+27=0

a = -15; b = 0; c = +27;
Δ = b2-4ac
Δ = 02-4·(-15)·27
Δ = 1620
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1620}=\sqrt{324*5}=\sqrt{324}*\sqrt{5}=18\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{5}}{2*-15}=\frac{0-18\sqrt{5}}{-30}
=-\frac{18\sqrt{5}}{-30}
=-\frac{3\sqrt{5}}{-5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{5}}{2*-15}=\frac{0+18\sqrt{5}}{-30}
=\frac{18\sqrt{5}}{-30}
=\frac{3\sqrt{5}}{-5}
$