(6-9x)/2-3=x/2

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Solution for (6-9x)/2-3=x/2 equation: 


x in (-oo:+oo)

(6-(9*x))/2-3 = x/2 // - x/2

(6-(9*x))/2-(x/2)-3 = 0

(6-9*x)/2-(x/2)-3 = 0

(6-9*x)/2-x/2-3 = 0

(6-9*x)/2-x/2+(-3*2)/2 = 0

6-9*x-x-3*2 = 0

6-10*x-6 = 0

-10*x = 0

(-10*x)/2 = 0

(-10*x)/2 = 0 // * 2

-10*x = 0

-10*x = 0 // : -10

x = 0

x = 0

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